x^2-440x+10000=0

Solution for x^2-440x+10000=0 equation:

x^2-440x+10000=0

a = 1; b = -440; c = +10000;
Δ = b2-4ac
Δ = -4402-4·1·10000
Δ = 153600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{153600}=\sqrt{25600*6}=\sqrt{25600}*\sqrt{6}=160\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-440)-160\sqrt{6}}{2*1}=\frac{440-160\sqrt{6}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-440)+160\sqrt{6}}{2*1}=\frac{440+160\sqrt{6}}{2}
$